12m+24m^2-36m^2=0

Solution for 12m+24m^2-36m^2=0 equation:

12m+24m^2-36m^2=0

We add all the numbers together, and all the variables

-12m^2+12m=0

a = -12; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-12)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-12}=\frac{-24}{-24}
=1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-12}=\frac{0}{-24}
=0
$